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BI SQL # 116 : SQL Server DBA Scripts : Find All Database table relation in 1-* format

Hi Geeks,

In this article we are going to cover How to Find All Database table relation in 1-* format.

In this post we are going to discuss following points:

  • Problem Statement of SQL Script:
  • Description of SQL Script:
  • SQL Script Output Column
  • SQL Script Code
  • SQL Script Output Screenshot
  • User Level to execute

 

Problem Statement of SQL Script:

How can find All database table relationship in 1-* format?

Description of SQL Script:

All database table relationship in 1-* format is for Documentation and high level table relationship findings.

SQL Script Output Column

TablesWithRelations

SQL Script Code

SELECT CASE 
        WHEN a.parent_object_id IS NULL
            THEN parent.NAME + '-1--*-' + child.NAME
        ELSE parent.NAME + '-1--1-' + child.NAME
        END AS TablesWithRelations
FROM (
    SELECT DISTINCT parent_object_id
        ,referenced_object_id
    FROM sys.foreign_keys
    ) fk
LEFT JOIN (
    SELECT DISTINCT fkindexes.parent_object_id
        ,fkindexes.referenced_object_id
    FROM (
        SELECT fk.parent_object_id
            ,fk.referenced_object_id
            ,ixcolumns.index_id
            ,COUNT(*) cindexes
        FROM (
            SELECT object_id
                ,parent_object_id
                ,referenced_object_id
            FROM (
                SELECT row_number() OVER (
                        PARTITION BY parent_object_id
                        ,referenced_object_id ORDER BY object_id
                        ) rid
                    ,object_id
                    ,parent_object_id
                    ,referenced_object_id
                FROM sys.foreign_keys
                ) fk
            WHERE rid = 1
            ) fk
        JOIN sys.foreign_key_columns fkc ON fkc.constraint_object_id = fk.
            object_id
        JOIN sys.index_columns ixcolumns ON ixcolumns.object_id = fkc.
            parent_object_id
            AND ixcolumns.column_id = fkc.parent_column_id
        JOIN sys.indexes ix ON ix.object_id = ixcolumns.object_id
            AND ix.index_id = ixcolumns.index_id
        WHERE ix.is_unique = 1
        GROUP BY fk.parent_object_id
            ,fk.referenced_object_id
            ,ixcolumns.index_id
        ) fkindexes
    JOIN (
        SELECT fk.parent_object_id
            ,ixcolumns.index_id
            ,COUNT(*) cindexestotal
        FROM (
            SELECT DISTINCT parent_object_id
            FROM sys.foreign_keys
            ) fk
        JOIN sys.index_columns ixcolumns ON ixcolumns.object_id = fk.
            parent_object_id
        GROUP BY fk.parent_object_id
            ,ixcolumns.index_id
        ) totalindexes ON totalindexes.parent_object_id = fkindexes.
        parent_object_id
        AND totalindexes.index_id = fkindexes.index_id
    WHERE cindexestotal - cindexes = 0
    ) a ON a.parent_object_id = fk.parent_object_id
    AND a.referenced_object_id = fk.referenced_object_id
JOIN sys.tables child ON fk.parent_object_id = child.object_id
JOIN sys.tables parent ON fk.referenced_object_id = parent.object_id
ORDER BY TablesWithRelations

SQL Script Output Screenshot

image

User Level to execute

    100

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